Mechanics

Work-Energy Theorem

Wnet=ΔKE=12mvf212mvi2W_{net} = \Delta KE = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2

Net work equals the change in kinetic energy.

Variables

W_net
Net work
Total work done
J
ΔKE
Change in KE
Final minus initial KE
J
m
Mass
Object mass
kg
v_f
Final velocity
Final speed
m/s
v_i
Initial velocity
Initial speed
m/s

Derivation

Integrate F = ma over displacement.

Your notes

0/5000