Mechanics

Projectile Range

R=v02sin(2θ)gR = \frac{v_0^2 \sin(2\theta)}{g}

Horizontal range of a projectile launched from ground level.

Variables

R
Range
Horizontal distance traveled
m
v₀
Initial velocity
Launch speed
m/s
θ
Launch angle
Angle above horizontal
°
g
Gravitational acceleration
≈ 9.8 m/s²
m/s²

Derivation

Combine horizontal and vertical motion equations, solve for x when y = 0.

Your notes

0/5000